1/2y^2-3/2y-5

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Solution for 1/2y^2-3/2y-5 equation: 


y in (-oo:+oo)

(1/2)*y^2-((3/2)*y)-5 = 0

(1/2)*y^2+(-3/2)*y-5 = 0

1/2*y^2-3/2*y-5 = 0

DELTA = (-3/2)^2-(-5*1/2*4)

DELTA = 49/4

DELTA > 0

y = ((49/4)^(1/2)+3/2)/(1/2*2) or y = (3/2-(49/4)^(1/2))/(1/2*2)

y = 5 or y = -2

y in { -2, 5 }

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